How to use class AesCmac with arbitrary key password length #137
Unanswered
arnulfrupp
asked this question in
Q&A
Replies: 1 comment 1 reply
-
I'm answering my own question. After reviewing RFC 4615 I found the following solution:
|
Beta Was this translation helpful? Give feedback.
1 reply
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
-
I'm trying to implement PBKDF2 with AES_CMAC_PRF_128 hash using this project.
The below code works with HMACSHA256. When replacing new HMACSHA256(..) with new AesCmac(..) I get:
How to I need to prepare the key correctly?
Beta Was this translation helpful? Give feedback.
All reactions